Chimney subjected to wind pressure
Tall structures like
tower, chimney, pillars, etc. are subjected due to wind pressers. They are
subjected by mainly two forces first one is its self-weight and another is
force due to wind. And due to these forces direct and bending stresses are
developed in tall structures. Direct stresses are developed due to self-weight
and bending stresses are developed due to wind pressures.
In above fig. 8 a
circular chimney of external diameter ‘D’ and internal ‘d’ is subjected due to
wind pressure of ‘p’. The wind pressure is applied on total height ‘H’ with external
diameter ‘D’. Therefore projected area of wind pressure is height ‘H’ multiplied
by width ‘D’.
Now, we know that
resultant stress


First discuss about
direct stress σ0 which is developed by self-weight of chimney.
We
know that
Where,
A =
Base area;
W = Self-weight;
W = Volume X density of masonry of chimney;
Here volume is depends
on shape of chimney,
Volume
for uniform circular cross section
= Base area X height
Where;
D = external diameter of chimney;
d = internal diameter of chimney;
H = height of chimney;
Volume for uniform rectangle
cross section
= Base area X height
Where;
B = external breadth of chimney;
D = external width of chimney;
b = internal breadth of chimney;
d = internal width of chimney;
H = height of chimney;
Volume for non-uniform
cross section
= Average cross sectional area X height
Now, discuss about
bending stress σb which is developed by wind pressure.
We
know thatHere,
P = Wind force;
P = Wind pressure X projected area;
Projected area:
Projected
area is the area where wind strike to chimney. Therefore this area equals to external
face where wind strike, multiplied by height of chimney. Wind pressure for
rectangular shape chimney is greater than as compare to circular shape because
of its circular shape. Therefore during calculation of wind force for
rectangular shape simply
P = Wind pressure X projected area
But for circular shape only it multiplied by
wind coefficient.
P = C X Wind pressure X projected area
Where,
C = wind coefficient;
e = eccentricity of
wind pressure = h/2;
Wind pressure act at
center of height of chimney.
Z =
section modulus
I = moment of inertia;
ymax = max centroidal distance = external dimension/2
1 comments
thanks a lot this information was soo useful i had problem with my assignment but now m soooo sorted thank yu
ReplyDelete