Combined Stress distribution at the base
Case– 1(σo>σb):
Answer of σmax in this case is +ve.
Since σo>σb answer of σmin in this case is +ve.
Case– 2(σo<σb):
Answer of σmax in this case is +ve.
Since σo<σb answer of σmin in this case is -ve.
Case– 3(σo=σb):
Answer of σmax in this case is +ve.
Since σo=σb answer of σmin in this case is zero.
Answer of σmax in this case is +ve.
Since σo>σb answer of σmin in this case is +ve.
The stress distribution
diagram is completely +ve as shown in fig.3.a. Hence stress distribution is
completely compressive.
Answer of σmax in this case is +ve.
Since σo<σb answer of σmin in this case is -ve.
The stress distribution
diagram is partially +ve and partially -ve as shown in fig.3.b. Hence stress distribution is partially compressive and partially tensile.
Answer of σmax in this case is +ve.
Since σo=σb answer of σmin in this case is zero.
The stress distribution diagram is completely +ve as shown in fig.3.a. Hence stress distribution is completely compressive. The stress distribution diagram is completely
+ve as shown in fig.3.c. Hence stress distribution is completely
compressive. This also called ‘No
tension condition’.
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